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Forward from: Dk.... The king
G α No of workers2
G α √(No. of Machines)
G α No of hours

a=sign of proportional
200 α 42 * √4 * 8
200 α 16 * 2 * 8
200 α 256
200 = k x 256
K =200/256=25/32

When 3 people work for 12 hours each with 9 machines,

produced is equal to ====== 25/32* 32 * √9 * 12 = 253.125


Forward from: Priya


Forward from: Yogesh
Maximum when expression in denominator minimum
49t^2-4t+2=0
98t-4=0
T=2/49
4/49-8/49+2
4-8+98/49=94/49
Put. 94/(94/49)=49


Forward from: Ankit Pandey
Solution plzz


Forward from: Yogesh
Speed diminished=k*√wagon
42-33=k*√9
K=3
As reduced by 42 engine can't move
42=3*√wagon
Wagon=196

Maximum wagon that can be pulled 195


Forward from: Unknown


Forward from: Yogesh
120*5/18=100/3 m/s
In 40 second 200m ahead
1 second 5 m
Distance of tata In 1 second 100/3
Difffernce is 5m in 1 second
100/3-a=5
85/3 m/s
In km/ hr. 85*18/3*5=102km/hr


Forward from: Aarushi Singla


Forward from: Hemant
√3+1--------1
2√2-----------√2(√3-1)

Area= √3/4 ×[2(4-2√3]
Area=2√3-3


Forward from: Unknown


Forward from: Kabali
A. 20. 3
60
B 30. 2
Yha ek full tank ki bat hai bt half A+B ne Kiya yani 30/5=6min
Total time 24 hai yahi bcha kitna 18 min
An half hai jo SAB karege
18........30
1min..... 5/3
A+B+C=5/3
5+C=5/3
Negative hai C=10/3
10/3..... 100lit
60min ... 1800lit


Forward from: Unknown


Forward from: Yogesh
110(1/4x)=55/2x
Remaining distance=110-55/2x
=220x-55/2x
2 nd day cover cover=220x-55/6xy
55/2x+220x-55/6xy=330/xy
165y+220x-55/6xy=330/xy
165y+220x-55=6*330
15y+20x=185
3y+4x=37

y=37-4x/3
Possible integer values
(1,11) (4,7)(7,3)

Distance covered after two hours=330/xy
330/1*11=30
330/4*7
330/3*7 no integer
Distance left =110-30=80


Forward from: Aarushi Singla


Forward from: Hemant
#concept


Grt sir ji👌👌🙏🙏🙈🙈


Forward from: Hemant


👌👌




Hmm

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