Kanalimiz obunachi
@Chemist_I7 dan yechim
14-misol
M=3.2•22.4=71.68g/mol
X1. X2
71.68
X1 71.68
X1=>M=32g/mol=>O2
X2=>M=84g/mol=>Kr
Kr (Odatda oksid hosil qilmaydi)❌
X2=>M=131g/mol=>Xe✅
Xe ning esa (XeO2;XeO3;XeO4) oksidlari mavjud!
XeOn==>Xe+0.5nO2
131+16n.
-----------------=71.68
1+0.5n
71.68+35.84n=131+16n
19.84n=59.32
n=3=>XeO3
O‘yuvchi barit=>Ba(OH)2
Ba(OH)2+XeO3=>BaXeO4
171---------------------------332
8.55----------------------x=16.6gr✔️
#A✅

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