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390). Price of Tomato in July, August and September in Mumbai = `40 + 56 + 56 per kg
= 152 kg
Price of Tomato in September, October and November in Nagpur = `8 + 56 + 48 per kg
= 112 kg
Required % = 152 × 100 / 112 = 135.71% ≈ 136%
Answer: a)


389). Total sale of Tomato in July = 500 × 25 / 100 = 125 tonnes
Total sales in Pune in July = 125 × 35 / 100 = 43.75 tonnes
Its total cost = 43.75 × 1000 × 32 = 1400000
Total sale of Tomato in September = 500 × 26 / 100 = 130 tonnes
Total sales in Thane in September = 130 × 55 / 100 = 71.50 tonnes
Its total cost = 71.50 × 1000 × 40 = 2860000
Required difference = 2860000 – 1400000
= 1460000
Answer: e)


388). Total sale of Tomato in October
= 500 × 15 / 100 = 75 tonnes
Total sale of Tomato in November = 500 × 12 / 100 = 60 tonnes
Total income in a month = (average rate that month in all cities × total quantity)
Total income in October = 32 × 75 × 1000 = `2400000
Total income in November = 40 × 60 × 1000 = `2400 000
Required difference = 2400000 – 2400000 = 0
Answer: c)


387). Average price of Tomato in Mumbai
= 1 / 6 × (40 + 56 + 56 + 48 + 56 + 40)
= `49.33 kg
Average price of Tomato in Pune
= 1 / 6 × (32 + 16 + 24 + 16 + 24 + 56)
= `28 per kg
Average price of Tomato in Nagpur
= 1 / 6 × (16 + 32 + 8 + 56 + 48 + 48)
= `34.66 per kg
Average rate of Tomato in Thane
= 1 / 6 × (24 + 48 + 40 + 8 + 32 + 32)
= `30.66 per kg
Thus the maximum average price is in Mumbai.
Answer: a)


386). Average price of Tomato in July
= 1 / 4 × (16 + 24 + 32 + 40) = 28 per kg
Average price of Tomato in August
= 1 / 4 × (16 + 32 + 48 + 56) = 38 per kg
Average price of Tomato in September
= 1 / 4 × (8 + 24 + 40 + 56) = 32 per kg
Average price of Tomato in October
= 1 / 4 × (8 + 16 + 48 + 56) = 32 per kg
Average price of Tomato in November
= 1 / 4 × (24 + 32 + 48 + 56) = 40 per kg
Average price of Tomato in December
= 1 / 4 × (32 + 40 + 48 + 56) = 44 per kg
In December the average price of Tomato per kg is the maximum and in July the average price of Tomato is the
minimum.
Answer: a)


385). From Graph (iii) : Ratio of market prices is Bajaj : M&M = 8x : 11x
11x – 8x = 3x = 1,08,000
x = 36,000
Now market price of Maruti = 5x = 180,000
Market price of Honda = 10x = 3,60,000
Required percentage = (3,60,000 - 180,000) / 3,60,000 × 100
= 180,000 / 3, 60,000 × 100
Required percentage = 50%.
Quicker Approach:
Ratio of price of Honda to Maruti = 2 : 1
Required ratio = (2-1)/2 × 100 = 50%
Note: There is no need of the cost of Bajaj car in March 2004.
Answer: b)


384). Ratio of price of all the given companies is
Toyoto : Bajaj : Maruti : Honda : M & M
3 : 2
8 : 5
1 : 2
10 : 11
= (3 × 8×1×10) : (2×8×1×10) : (2×5×1×10) : (2×5×2×10) : (2×5×2×11)
= 240 : 160 : 100 : 200 : 220 = 12 : 8 : 5 : 10 : 11
Volumes of production of Toyota, Bajaj, Maruti, Honda and M&M in March 2004 are in the ratio 1 : 2 : 2 : 1 : 2
Let x be present in the ratio of the price of each of the cars.
Average price in March 2004 = (12x×1+ 8x×2 + 5x×2 + 10x×1 + 11x×2) / (1+2+2+1+2) = 70x/8 = 8.75x
Therefore the prices of Toyota, Honda and M&M are greater than the average price of all cars in March 2004.
Answer: c)


383). If a Honda car costs Rs 2.5 lakhs,
Then a Bajaj car will cost  Honda / Maruti = 2  Maruti = 2.5/2 = 5/4
Maruti / Bajaj = 0.625  Bajaj = 5/ (4 × 0.625) = 2 lakhs
Sales of Bajaj cars in March 2004 = (25/100) ×50000×2 = 25000 lakhs.
Answer: c)

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