72)
Al + 3HCl = AlCl3 + 1.5H2
Mg + 2HCl = MgCl2 + H2
Ozimizdan 6 mol H2 olsak 4 mol aluminiydan hosil boladi
6/2=3 mol Mg hosil bolgan H2
4•27=108
3•24=72
72+108 -------- 72 g Mg
45g ----------x=18
#d.
Orifjonov_Shohrux✍
Al + 3HCl = AlCl3 + 1.5H2
Mg + 2HCl = MgCl2 + H2
Ozimizdan 6 mol H2 olsak 4 mol aluminiydan hosil boladi
6/2=3 mol Mg hosil bolgan H2
4•27=108
3•24=72
72+108 -------- 72 g Mg
45g ----------x=18
#d.
Orifjonov_Shohrux✍