73)
100•1.095=109.5
100% --------109.5
30% ------x=32.85 HCl eritmasi
4NaOH + 4HCl =....
Ba(OH)2 + 2HCl =...
6•36.5---------- 1 mol BaSO4
32.85 -------x=0.15
#d.
#Orifjonov_Shohrux✍
100•1.095=109.5
100% --------109.5
30% ------x=32.85 HCl eritmasi
4NaOH + 4HCl =....
Ba(OH)2 + 2HCl =...
6•36.5---------- 1 mol BaSO4
32.85 -------x=0.15
#d.
#Orifjonov_Shohrux✍