Quantitative Questions on Ages pt. 1
Q1. The sum of the ages of A and B is 63 years. After 6 years, the age of B will be four times that of the A. What is the age of B?
(a) 46 Years
(b) 50 Years
(c) 53 Years
(d) 60 Years
Answer: (c) 53 Years
Let the Present Age of A is x years
So the Present Age of B = (63 – x) Years
After 6 Years,
(63 – x) + 6 = 4(x + 6)
69 – x = 4x + 24
5x = 45
x = 9
So the present age of B is = (63 – x)= 63 – 9= 53 Years
Q2. Rohit is twice as old as Rakesh was two years ago. If the difference between their ages be 4 years, how old is Rohit today?
(a) 5 Years
(b) 8 Years
(c) 10 Years
(d) 12 Years
Answer: (d) 12 Years
Let the age of Rakesh two year ago is x years
So the Present Age of Rohit is 2x Years and Present age of Rakesh is (x + 2) Years
So,
2x – (x + 2) = 4
2x – x – 2 = 4
x = 6
So the present age of Rohit is = 2 X 6 = 12 Years
Q3. The sum of the ages of 4 children born at the intervals of 3 years each is 42 years. What is the age of the youngest child ?
(a) 4 Years
(b) 6 Years
(c) 9 Years
(d) 10 Years
Answer: (b) 6 Years
Let the age of the youngest child is x years. So the age of other childs will be (x + 3), (x + 6) and (x + 9)
x + (x + 3) + (x + 6) + (x + 9) = 42
4x = 42 – 18
x = 6
So the age of the youngest child is = 6 Years
Q4. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27 years, then how old is B ?
(a) 9 Years
(b) 10 Years
(c) 7 Years
(d) 8 Years
Answer: (b) 10 Years
Let the age of C be x years, then the age of B = 2x and age of A = 2x + 2
Then, x + 2x + 2x + 2 = 27
5x = 25
x = 5
So the age of the B is = 2x = 2 X 5 = 10 Years
Q5. The sum of the present ages of a father and his son is 60 years. Six year ago, father’s age was five times the age of the son. After 6 years, son’s age will be ?
(a) 12 Years
(b) 16 Years
(c) 20 Years
(d) 24 Years
Answer: (c) 20 Years
Let the present age of son is x, so the age of father will be (60 – x)
Then, six years ago
(60 – x) -6 = 5(x – 6)
6x = 84
x = 14
So the age of son after 6 years = (x + 6) = 14 + 6 = 20 Years
Q1. The sum of the ages of A and B is 63 years. After 6 years, the age of B will be four times that of the A. What is the age of B?
(a) 46 Years
(b) 50 Years
(c) 53 Years
(d) 60 Years
Answer: (c) 53 Years
Let the Present Age of A is x years
So the Present Age of B = (63 – x) Years
After 6 Years,
(63 – x) + 6 = 4(x + 6)
69 – x = 4x + 24
5x = 45
x = 9
So the present age of B is = (63 – x)= 63 – 9= 53 Years
Q2. Rohit is twice as old as Rakesh was two years ago. If the difference between their ages be 4 years, how old is Rohit today?
(a) 5 Years
(b) 8 Years
(c) 10 Years
(d) 12 Years
Answer: (d) 12 Years
Let the age of Rakesh two year ago is x years
So the Present Age of Rohit is 2x Years and Present age of Rakesh is (x + 2) Years
So,
2x – (x + 2) = 4
2x – x – 2 = 4
x = 6
So the present age of Rohit is = 2 X 6 = 12 Years
Q3. The sum of the ages of 4 children born at the intervals of 3 years each is 42 years. What is the age of the youngest child ?
(a) 4 Years
(b) 6 Years
(c) 9 Years
(d) 10 Years
Answer: (b) 6 Years
Let the age of the youngest child is x years. So the age of other childs will be (x + 3), (x + 6) and (x + 9)
x + (x + 3) + (x + 6) + (x + 9) = 42
4x = 42 – 18
x = 6
So the age of the youngest child is = 6 Years
Q4. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27 years, then how old is B ?
(a) 9 Years
(b) 10 Years
(c) 7 Years
(d) 8 Years
Answer: (b) 10 Years
Let the age of C be x years, then the age of B = 2x and age of A = 2x + 2
Then, x + 2x + 2x + 2 = 27
5x = 25
x = 5
So the age of the B is = 2x = 2 X 5 = 10 Years
Q5. The sum of the present ages of a father and his son is 60 years. Six year ago, father’s age was five times the age of the son. After 6 years, son’s age will be ?
(a) 12 Years
(b) 16 Years
(c) 20 Years
(d) 24 Years
Answer: (c) 20 Years
Let the present age of son is x, so the age of father will be (60 – x)
Then, six years ago
(60 – x) -6 = 5(x – 6)
6x = 84
x = 14
So the age of son after 6 years = (x + 6) = 14 + 6 = 20 Years